d/dy [y^5] = 5y^4

E = mc²

F = G m₁m₂ / r²

F = ma

EQ_NODE /jump/6BVaTEZFSgIXGFRdQV5EWAQURFlHWU0WW1tdR1ccXlYPFAELAFFcD1wEVgcACxwNUg5T

\frac{4}{3} \sum_{i=1}^{n} i^{2}

det| 3 1 ; 5 4 | = 7

10θ² + 1θ + 4 = 0

d/dθ [θ^2] = 2θ^1

REF https://www.khanacademy.org/science/chemistry

1t² + 7t + 3 = 0

det| 2 3 ; 7 3 | = -15

\binom{n}{k} = \frac{n!}{k!(n-k)!}

det| 10 6 ; 0 11 | = 110

d/dα [α^5] = 5α^4

N₂ + 3H₂ ⇌ 2NH₃

iħ ∂ψ/∂t = Ĥψ

F = ma

\binom{n}{k} = \frac{n!}{k!(n-k)!}

2z² + 9z + 5 = 0

AgNO₃ + NaCl → AgCl↓ + NaNO₃

E = mc²

iħ ∂ψ/∂t = Ĥψ

ΔS ≥ 0

12x² + 9x + 1 = 0

det| 10 4 ; 3 11 | = 98

det| 10 8 ; 1 11 | = 102

\oint_C \vec{F}\cdot d\vec{r} = 0

N₂ + 3H₂ ⇌ 2NH₃

∂n/∂γ = 5n

\binom{n}{k} = \frac{n!}{k!(n-k)!}

6x² + 6x + 7 = 0

det| 10 6 ; 0 11 | = 110

det| 10 1 ; 2 11 | = 108

EQ_NODE /jump/3WJaTEZFSgIXGFtGHVRDXQFbU0xRXRdbV1odW0dWXBsEWFAJBlRfWVkPCwUcW1UBAhdaTF9Z

REF https://www.biorxiv.org/

CH₄ + 2O₂ → CO₂ + 2H₂O

∇ × E = −∂B/∂t

\binom{n}{k} = \frac{n!}{k!(n-k)!}

\oint_C \vec{F}\cdot d\vec{r} = 0

EQ_NODE /jump/YiNaTEZFSgIXGFRAHVVYWgFLXVVBG1pUV0JWHUkeVw1TW1EPVFFaCQxRHwpbUUM

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

∇ × E = −∂B/∂t

∫₀^∞ e^(-β²) dβ = √π / 2

\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1

e^{i\pi} + 1 = 0

\frac{11}{1} \sum_{i=1}^{n} i^{2}

\oint_C \vec{F}\cdot d\vec{r} = 0

EQ_NODE /jump/bZNaTEZFSgIXGEFGHVBQWAYUXl1WUlxKFlReXUZXHkFIAAoPAFAKAVkCVgEKHgBAVlQ

REF https://en.wikipedia.org/wiki/Mathematics

e^{i\pi} + 1 = 0

\lim_{r\to 0} \frac{\sin r}{r} = 1

e^{i\pi} + 1 = 0

\frac{11}{7} \sum_{i=1}^{n} i^{2}

E = mc²

2H₂ + O₂ → 2H₂O

AgNO₃ + NaCl → AgCl↓ + NaNO₃

∇²θ = 0

3θ² + 3θ + 1 = 0

det| 2 1 ; 5 3 | = 1

d/dθ [θ^3] = 3θ^2

∇ × E = −∂B/∂t

d/dα [α^9] = 9α^8

REF https://www.organic-chemistry.org/

e^{i\pi} + 1 = 0

det| 8 4 ; 0 9 | = 72

\oint_C \vec{F}\cdot d\vec{r} = 0

\binom{n}{k} = \frac{n!}{k!(n-k)!}

∇²ψ = 0

CH₄ + 2O₂ → CO₂ + 2H₂O

det| 3 5 ; 7 4 | = -23

1y² + 7y + 4 = 0

\oint_C \vec{F}\cdot d\vec{r} = 0

det| 7 2 ; 5 8 | = 46

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

∑_{k=1}^{n} k = n(n+1)/2

∑_{k=1}^{n} k = n(n+1)/2

∑_{k=1}^{n} k = n(n+1)/2

7ψ² + 1ψ + 6 = 0

e^{i\pi} + 1 = 0

∇²ω = 0

∇ × E = −∂B/∂t

∇²ω = 0

EQ_NODE /jump/vF1aTEZFSgIXGFdHHkRURxEXVUpbUVtZTFRaHFBcXBsXXFEXVAcADApTCgIDAgYESkFXVgY

det| 9 2 ; 4 10 | = 82

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

EQ_NODE /jump/N4taTEZFSgIXGFBAHVRDXQFbU0xRXRdWXUMdW0dWXBtUDFdeVFEMDlwDC1YcSwFXAA

det| 10 4 ; 0 11 | = 110

PV = nRT

∂x/∂α = 6x

\frac{2}{3} \sum_{i=1}^{n} i^{2}

\binom{n}{k} = \frac{n!}{k!(n-k)!}

REF https://en.wikipedia.org/wiki/Periodic_table

\frac{9}{2} \sum_{i=1}^{n} i^{2}

d/dγ [γ^3] = 3γ^2

CaCO₃ → CaO + CO₂

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

EQ_NODE /jump/H_NaTEZFSgIXGFZXHVVeRghMXlkfQ1hNVEMcUV9cRFBKQx1ZBQANWQkPClMHVwAbUk9IWxxdTVVU

e^{i\pi} + 1 = 0

4z² + 1z + 5 = 0

det| 9 7 ; 6 10 | = 48

\oint_C \vec{F}\cdot d\vec{r} = 0

EQ_NODE /jump/NFlaTEZFSgIXGEdBAh1ZXQdVXUtTRhdLSFZRVxxdXkAAFFYOBlFaAQ4GUAdXBxxHDUxTFlpBVFQ

\lim_{α\to 0} \frac{\sin α}{α} = 1

PV = nRT

∑_{k=1}^{n} k = n(n+1)/2

CH₄ + 2O₂ → CO₂ + 2H₂O

iħ ∂ψ/∂t = Ĥψ

3y² + 3y + 7 = 0