Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:04Z
E = mc²
2ω² + 4ω + 5 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
90K
det| 9 4 ; 1 10 | = 86
438K
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
394K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
CH₄ + 2O₂ → CO₂ + 2H₂O
94K
det| 5 6 ; 7 6 | = -12
211K
det| 2 1 ; 2 3 | = 4
det| 7 1 ; 7 8 | = 49
390K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}