Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:08Z
E = mc²
2ω² + 4ω + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
438K
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
394K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 2 1 ; 2 3 | = 4
CH₄ + 2O₂ → CO₂ + 2H₂O
390K
∫₀^∞ e^(-φ²) dφ = √π / 2
69K
det| 9 4 ; 1 10 | = 86
144K