Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:55Z
E = mc²
2ω² + 4ω + 5 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
438K
E = mc²
∫₀^∞ e^(-x²) dx = √π / 2
29K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
\lim_{x\to 0} \frac{\sin x}{x} = 1
94K
det| 2 1 ; 2 3 | = 4
∑_{k=1}^{n} k = n(n+1)/2
390K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 7 4 ; 4 8 | = 40
144K
2H₂ + O₂ → 2H₂O