Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:57Z
E = mc²
det| 9 4 ; 1 10 | = 86
144K
2ω² + 4ω + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
90K
CH₄ + 2O₂ → CO₂ + 2H₂O
438K
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
394K
det| 12 9 ; 5 13 | = 111
29K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 4 6 ; 4 5 | = -4
94K
det| 10 1 ; 6 11 | = 104
211K
det| 2 1 ; 2 3 | = 4
det| 8 9 ; 4 9 | = 36
69K