Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-19 23:03Z
3θ² + 8θ + 7 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
222K
∇ × E = −∂B/∂t
∑_{k=1}^{n} k = n(n+1)/2
87K
\frac{12}{3} \sum_{i=1}^{n} i^{2}
\lim_{β\to 0} \frac{\sin β}{β} = 1
174K
λ = h/p
\lim_{z\to 0} \frac{\sin z}{z} = 1
335K
iħ ∂ψ/∂t = Ĥψ
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
472K
det| 7 4 ; 4 8 | = 40
392K