Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:53Z
E = mc²
det| 1 4 ; 2 2 | = -6
320K
det| 7 8 ; 6 8 | = 8
144K
2ω² + 4ω + 5 = 0
E = mc²
CH₄ + 2O₂ → CO₂ + 2H₂O
394K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
94K
det| 2 1 ; 2 3 | = 4
det| 9 4 ; 1 10 | = 86
390K