Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:41Z
E = mc²
d/dz [z^11] = 11z^10
320K
2ω² + 4ω + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
438K
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
394K
det| 7 4 ; 4 8 | = 40
29K
det| 7 1 ; 7 8 | = 49
211K
∑_{k=1}^{n} k = n(n+1)/2
69K