Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:42Z
E = mc²
det| 9 5 ; 1 10 | = 85
320K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
144K
2ω² + 4ω + 5 = 0
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
394K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
94K
det| 9 4 ; 1 10 | = 86
390K
\frac{8}{6} \sum_{i=1}^{n} i^{2}
69K
∑_{k=1}^{n} k = n(n+1)/2
144K