Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:57Z
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
144K
2ω² + 4ω + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
90K
d/dz [z^11] = 11z^10
438K
E = mc²
\frac{9}{8} \sum_{i=1}^{n} i^{2}
\frac{7}{1} \sum_{i=1}^{n} i^{2}
211K
det| 2 1 ; 2 3 | = 4
det| 7 4 ; 4 8 | = 40
390K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\lim_{x\to 0} \frac{\sin x}{x} = 1
352K