Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:09Z
E = mc²
2ω² + 4ω + 5 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
90K
E = mc²
\frac{9}{8} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
94K
det| 2 1 ; 2 3 | = 4
∑_{k=1}^{n} k = n(n+1)/2
390K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
69K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 7 1 ; 7 8 | = 49
352K