Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:17Z
E = mc²
2ω² + 4ω + 5 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
90K
E = mc²
CH₄ + 2O₂ → CO₂ + 2H₂O
29K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 7 4 ; 4 8 | = 40
94K
det| 12 3 ; 4 13 | = 144
211K
det| 2 1 ; 2 3 | = 4
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}