Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:26Z
E = mc²
det| 4 8 ; 3 5 | = -4
144K
2ω² + 4ω + 5 = 0
E = mc²
det| 9 2 ; 3 10 | = 84
394K
∫₀^∞ e^(-x²) dx = √π / 2
29K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 2 1 ; 2 3 | = 4
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
390K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\lim_{β\to 0} \frac{\sin β}{β} = 1
144K
2H₂ + O₂ → 2H₂O