Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-20 14:31Z
∫₀^∞ e^(-β²) dβ = √π / 2
3t² + 2t + 6 = 0
∂z/∂ω = 5z
det| 7 4 ; 4 8 | = 40
165K
4φ² + 9φ + 7 = 0
\frac{2}{4} \sum_{i=1}^{n} i^{2}
8θ² + 6θ + 1 = 0
e^{i\pi} + 1 = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∫₀^∞ e^(-θ²) dθ = √π / 2