Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:09Z
E = mc²
\frac{2}{2} \sum_{i=1}^{n} i^{2}
320K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
144K
2ω² + 4ω + 5 = 0
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
90K
E = mc²
det| 12 1 ; 5 13 | = 151
29K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
∫₀^∞ e^(-β²) dβ = √π / 2
94K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
211K
det| 9 4 ; 1 10 | = 86
390K
∑_{k=1}^{n} k = n(n+1)/2
144K