Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:57Z
E = mc²
2ω² + 4ω + 5 = 0
det| 9 5 ; 6 10 | = 60
438K
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
394K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
∫₀^∞ e^(-t²) dt = √π / 2
211K
det| 2 1 ; 2 3 | = 4
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
144K
2H₂ + O₂ → 2H₂O