Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:48Z
E = mc²
\lim_{r\to 0} \frac{\sin r}{r} = 1
144K
2ω² + 4ω + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
438K
E = mc²
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 9 4 ; 1 10 | = 86
94K
CH₄ + 2O₂ → CO₂ + 2H₂O
211K
det| 2 1 ; 2 3 | = 4
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 11 2 ; 5 12 | = 122
2H₂ + O₂ → 2H₂O