Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:54Z
E = mc²
CH₄ + 2O₂ → CO₂ + 2H₂O
144K
2ω² + 4ω + 5 = 0
E = mc²
\frac{2}{2} \sum_{i=1}^{n} i^{2}
394K
\lim_{t\to 0} \frac{\sin t}{t} = 1
29K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 2 1 ; 2 3 | = 4
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
69K
\lim_{z\to 0} \frac{\sin z}{z} = 1
144K