Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-19 21:27Z
10t² + 3t + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
66K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
2K
8ψ² + 2ψ + 2 = 0
det| 7 4 ; 4 8 | = 40
61K
det| 2 7 ; 7 3 | = -43
335K
det| 9 5 ; 6 10 | = 60
472K