Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:56Z
E = mc²
det| 8 6 ; 5 9 | = 42
144K
2ω² + 4ω + 5 = 0
det| 9 9 ; 5 10 | = 45
90K
\frac{4}{6} \sum_{i=1}^{n} i^{2}
438K
E = mc²
∫₀^∞ e^(-x²) dx = √π / 2
394K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 12 3 ; 4 13 | = 144
211K
det| 2 1 ; 2 3 | = 4
det| 1 2 ; 4 2 | = -6
390K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
144K