Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:43Z
E = mc²
2ω² + 4ω + 5 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
90K
\lim_{z\to 0} \frac{\sin z}{z} = 1
438K
E = mc²
Fe₂O₃ + 3CO → 2Fe + 3CO₂
394K
∫₀^∞ e^(-β²) dβ = √π / 2
29K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 2 4 ; 4 3 | = -10
211K
det| 2 1 ; 2 3 | = 4
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}