Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:08Z
E = mc²
2ω² + 4ω + 5 = 0
∫₀^∞ e^(-x²) dx = √π / 2
90K
E = mc²
\lim_{r\to 0} \frac{\sin r}{r} = 1
394K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 2 1 ; 2 3 | = 4
CH₄ + 2O₂ → CO₂ + 2H₂O
69K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
144K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
352K
2H₂ + O₂ → 2H₂O