Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:38Z
E = mc²
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
144K
2ω² + 4ω + 5 = 0
∫₀^∞ e^(-β²) dβ = √π / 2
438K
E = mc²
\frac{6}{3} \sum_{i=1}^{n} i^{2}
394K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 2 1 ; 2 3 | = 4
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}