Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:57Z
E = mc²
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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2ω² + 4ω + 5 = 0
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
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\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 12 1 ; 5 13 | = 151
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det| 2 1 ; 2 3 | = 4
det| 9 4 ; 1 10 | = 86
144K