Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:59Z
E = mc²
2ω² + 4ω + 5 = 0
det| 1 4 ; 0 2 | = 2
438K
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
29K
det| 9 4 ; 1 10 | = 86
211K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
390K
∫₀^∞ e^(-t²) dt = √π / 2
69K
∑_{k=1}^{n} k = n(n+1)/2
144K
∫₀^∞ e^(-β²) dβ = √π / 2
352K