Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-19 22:05Z
4α² + 7α + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
66K
CH₄ + 2O₂ → CO₂ + 2H₂O
5θ² + 1θ + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
61K
λ = h/p
det| 7 9 ; 1 8 | = 47
380K
det| 7 4 ; 4 8 | = 40
335K
∑_{k=1}^{n} k = n(n+1)/2
det| 4 6 ; 4 5 | = -4
119K
ΔS ≥ 0