Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:43Z
E = mc²
2ω² + 4ω + 5 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
438K
E = mc²
\lim_{t\to 0} \frac{\sin t}{t} = 1
394K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 9 7 ; 3 10 | = 69
94K
\lim_{γ\to 0} \frac{\sin γ}{γ} = 1
211K
det| 2 1 ; 2 3 | = 4
det| 11 2 ; 5 12 | = 122
69K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\frac{12}{7} \sum_{i=1}^{n} i^{2}
144K
2H₂ + O₂ → 2H₂O