Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-19 20:58Z
det| 4 8 ; 7 5 | = -36
det| 7 4 ; 4 8 | = 40
222K
∇ × E = −∂B/∂t
∑_{k=1}^{n} k = n(n+1)/2
2K
5β² + 3β + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
61K
∑_{k=1}^{n} k = n(n+1)/2
380K
CH₄ + 2O₂ → CO₂ + 2H₂O
335K