Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:59Z
E = mc²
det| 9 4 ; 1 10 | = 86
144K
2ω² + 4ω + 5 = 0
\lim_{x\to 0} \frac{\sin x}{x} = 1
90K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
438K
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
29K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 2 1 ; 2 3 | = 4
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
69K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∑_{k=1}^{n} k = n(n+1)/2
144K
det| 7 3 ; 6 8 | = 38
352K