Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-19 22:55Z
4α² + 7α + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
222K
CH₄ + 2O₂ → CO₂ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
87K
5θ² + 1θ + 7 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
61K
λ = h/p
∑_{k=1}^{n} k = n(n+1)/2
det| 7 4 ; 4 8 | = 40
472K
ΔS ≥ 0
N₂ + 3H₂ ⇌ 2NH₃
det| 3 4 ; 0 4 | = 12
det| 12 3 ; 6 13 | = 138