Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:33Z
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
320K
det| 7 4 ; 4 8 | = 40
144K
2ω² + 4ω + 5 = 0
E = mc²
det| 1 2 ; 4 2 | = -6
394K
∑_{k=1}^{n} k = n(n+1)/2
390K
CH₄ + 2O₂ → CO₂ + 2H₂O
69K