Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:59Z
E = mc²
d/dz [z^11] = 11z^10
320K
∑_{k=1}^{n} k = n(n+1)/2
144K
2ω² + 4ω + 5 = 0
E = mc²
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 9 4 ; 1 10 | = 86
94K
det| 4 6 ; 4 5 | = -4
211K
det| 2 1 ; 2 3 | = 4
∑_{k=1}^{n} k = n(n+1)/2
69K