Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:57Z
E = mc²
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
320K
2ω² + 4ω + 5 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
90K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
438K
E = mc²
det| 5 6 ; 7 6 | = -12
394K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 4 6 ; 0 5 | = 20
94K
det| 2 1 ; 2 3 | = 4
\binom{n}{k} = \frac{n!}{k!(n-k)!}