Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:12Z
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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2ω² + 4ω + 5 = 0
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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\frac{9}{8} \sum_{i=1}^{n} i^{2}
\lim_{z\to 0} \frac{\sin z}{z} = 1
94K
det| 12 9 ; 5 13 | = 111
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det| 2 1 ; 2 3 | = 4
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∑_{k=1}^{n} k = n(n+1)/2
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