Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:10Z
E = mc²
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
144K
2ω² + 4ω + 5 = 0
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
90K
E = mc²
\lim_{x\to 0} \frac{\sin x}{x} = 1
394K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
\lim_{β\to 0} \frac{\sin β}{β} = 1
211K
det| 9 4 ; 1 10 | = 86
390K
∑_{k=1}^{n} k = n(n+1)/2
144K