Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:13Z
E = mc²
det| 9 5 ; 6 10 | = 60
320K
2ω² + 4ω + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
438K
E = mc²
\frac{9}{8} \sum_{i=1}^{n} i^{2}
CH₄ + 2O₂ → CO₂ + 2H₂O
94K
d/dz [z^11] = 11z^10
211K
det| 2 1 ; 2 3 | = 4
det| 9 4 ; 1 10 | = 86
69K