Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:54Z
E = mc²
2ω² + 4ω + 5 = 0
E = mc²
d/dz [z^11] = 11z^10
394K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
94K
det| 2 1 ; 2 3 | = 4
det| 4 8 ; 3 5 | = -4
390K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 11 2 ; 5 12 | = 122