Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:02Z
E = mc²
2ω² + 4ω + 5 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
438K
E = mc²
det| 8 9 ; 4 9 | = 36
29K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 7 7 ; 4 8 | = 28
94K
det| 2 1 ; 2 3 | = 4
det| 7 4 ; 4 8 | = 40
390K
\frac{11}{6} \sum_{i=1}^{n} i^{2}
69K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
2H₂ + O₂ → 2H₂O