Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:42Z
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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2ω² + 4ω + 5 = 0
\lim_{γ\to 0} \frac{\sin γ}{γ} = 1
90K
E = mc²
det| 7 4 ; 4 8 | = 40
29K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
\frac{12}{7} \sum_{i=1}^{n} i^{2}
94K
det| 2 1 ; 2 3 | = 4
det| 1 2 ; 7 2 | = -12
69K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
352K