Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:09Z
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
320K
2ω² + 4ω + 5 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
438K
E = mc²
\frac{4}{6} \sum_{i=1}^{n} i^{2}
394K
det| 9 4 ; 1 10 | = 86
29K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
\frac{8}{7} \sum_{i=1}^{n} i^{2}
211K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
69K