Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:50Z
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
320K
2ω² + 4ω + 5 = 0
det| 9 4 ; 1 10 | = 86
438K
E = mc²
det| 4 6 ; 4 5 | = -4
29K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
∫₀^∞ e^(-x²) dx = √π / 2
94K
CH₄ + 2O₂ → CO₂ + 2H₂O
144K