Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:59Z
E = mc²
2ω² + 4ω + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
438K
E = mc²
\frac{12}{6} \sum_{i=1}^{n} i^{2}
394K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 7 9 ; 1 8 | = 47
211K
det| 2 1 ; 2 3 | = 4
\binom{n}{k} = \frac{n!}{k!(n-k)!}
69K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
d/dz [z^11] = 11z^10
144K
2H₂ + O₂ → 2H₂O