Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-19 22:00Z
4α² + 7α + 5 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
5θ² + 1θ + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
174K
∑_{k=1}^{n} k = n(n+1)/2
61K
λ = h/p
det| 10 1 ; 6 11 | = 104
335K
∑_{k=1}^{n} k = n(n+1)/2
CH₄ + 2O₂ → CO₂ + 2H₂O
32K