Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-19 23:46Z
3θ² + 8θ + 7 = 0
∇ × E = −∂B/∂t
∫₀^∞ e^(-φ²) dφ = √π / 2
87K
det| 10 2 ; 3 11 | = 104
2K
\frac{12}{3} \sum_{i=1}^{n} i^{2}
det| 5 6 ; 4 6 | = 6
174K
λ = h/p
det| 7 4 ; 4 8 | = 40
380K
iħ ∂ψ/∂t = Ĥψ
∑_{k=1}^{n} k = n(n+1)/2
119K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
d/dβ [β^11] = 11β^10