Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:54Z
E = mc²
\lim_{β\to 0} \frac{\sin β}{β} = 1
320K
2ω² + 4ω + 5 = 0
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
29K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
∫₀^∞ e^(-φ²) dφ = √π / 2
211K
∑_{k=1}^{n} k = n(n+1)/2
390K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
69K
det| 7 4 ; 4 8 | = 40
144K
\lim_{x\to 0} \frac{\sin x}{x} = 1
352K