Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-19 23:54Z
3θ² + 8θ + 7 = 0
∇ × E = −∂B/∂t
\lim_{r\to 0} \frac{\sin r}{r} = 1
2K
\frac{12}{3} \sum_{i=1}^{n} i^{2}
det| 10 7 ; 3 11 | = 89
61K
λ = h/p
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
380K
iħ ∂ψ/∂t = Ĥψ
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
d/dβ [β^11] = 11β^10