Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:48Z
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
320K
2ω² + 4ω + 5 = 0
\lim_{t\to 0} \frac{\sin t}{t} = 1
438K
E = mc²
det| 7 6 ; 1 8 | = 50
29K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 7 4 ; 4 8 | = 40
211K
det| 2 1 ; 2 3 | = 4
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
69K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
352K