Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:10Z
E = mc²
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
144K
2ω² + 4ω + 5 = 0
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
394K
∑_{k=1}^{n} k = n(n+1)/2
29K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
390K
det| 8 9 ; 4 9 | = 36
144K