Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:56Z
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
144K
2ω² + 4ω + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
90K
E = mc²
det| 7 9 ; 1 8 | = 47
394K
det| 10 7 ; 3 11 | = 89
29K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 2 1 ; 2 3 | = 4
det| 5 6 ; 1 6 | = 24
390K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\lim_{β\to 0} \frac{\sin β}{β} = 1
144K
2H₂ + O₂ → 2H₂O