Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-19 21:06Z
10t² + 3t + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
222K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
2K
8ψ² + 2ψ + 2 = 0
det| 7 4 ; 4 8 | = 40
174K
det| 2 7 ; 7 3 | = -43
61K
∑_{k=1}^{n} k = n(n+1)/2
472K
det| 12 1 ; 5 13 | = 151
392K